Quadratic function

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Sjell

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The vertical height of a ball in metres at any given time in seconds is by formula h=15t-t2 if I have formulated my graph how do I determine how long it will take after time t=0 for the ball to hit the ground ?I have attached my graph
IMG_20200826_123645.jpg
 
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Sjell said:
The vertical height of a ball in metres at any given time in seconds is by formula h=15t-t2 if I have formulated my graph how do I determine how long it will take after time t=0 for the ball to hit the ground ?I have attached my graph
View attachment 21189
Click to expand...
You have to solve for 't' from:

t2 - 15*t + h = 0

Above is a Quadratic equation in 't'. Find the roots of the quadratic equation using quadratic formula.

Please show us what you have tried and exactly where you are stuck.

Please follow the rules of posting in this forum, as enunciated at:


Please share your work/thoughts about this problem.
 
The problem says that h is "the vertical height of a ball". The "vertical height" is the height above the ground so the ball will hit the ground when h=0. That is why Subhotosh Kahn says you need to solve the quadratic equation \(\displaystyle t^2- 15t= 0\) (I don't know why he has "+ h", h= 0).
 
HallsofIvy said:
The problem says that h is "the vertical height of a ball". The "vertical height" is the height above the ground so the ball will hit the ground when h=0. That is why Subhotosh Kahn says you need to solve the quadratic equation \(\displaystyle t^2- 15t= 0\) (I don't know why he has "+ h", h= 0).
Click to expand...
Misread the problem! Corner time.......
 
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