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quadratic formula
- Thread starter preapgirl
- Start date
D
Deleted member 4993
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preapgirl said:using the quadratic formula
-b square rooted b squared - 4ac
** you only have o choose one please
y=axsquared+ bx+ c
please show work
problems:
xsquared-5x+4=0
2xsquared= 7x-3
xsquared-6x-7=0
4xsquared-4x-3=0
As written - your post does not make sense to me.
Please review your post - and post the COMPLETE problem as it was presented to you.
preapgirl said:using the quadratic formula
-b square rooted b squared - 4ac
** you only have o choose one please
y=axsquared+ bx+ c
please show work
problems:
xsquared-5x+4=0
2xsquared= 7x-3
xsquared-6x-7=0
4xsquared-4x-3=0
Hi preapgirl,
This is pretty much what we call "plug and chug" using the quadratic formula.
Set up the equation in descending order of the exponents, identify a, b, and c, then "plug and chug"
[1] \(\displaystyle x^2-5x+4=0\)
\(\displaystyle x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\)
\(\displaystyle a=1\:,\:b=-5\:,\:c=4\)
\(\displaystyle x=\frac{-^-5 \pm \sqrt{(-5)^2-4(1)(4)}}{2(1)}\)
That is NOT the quadratic formula. The quadratic formula is:preapgirl said:using the quadratic formula
-b square rooted b squared - 4ac
x = [-b plus or minus square root of b squared minus 4ac] divided by 2a
and is SHOWN this way:
x = [-b +- SQRT(b^2 - 4ac)] / (2a)
If you didn't know the proper formula, you're sure not ready for this.
I suggest you have a talk with your teacher.
Did you not see my post at all? Wow!preapgirl said:well my algebra should me this so its what he taught us by u know so im sorry