Can somebody prove this for me?
x= ((-b+-sqrt{b^2-4ac})/2a -- this is the usual quadratic formula which you use to solve for for x.
But if you have this one:
{2c}/{-b+-(b^2-4ac)}
Can I also always use this formular for solving? Or is there a different. Can you prove that it doesn't work?
Thanks a lot
Roman
x= ((-b+-sqrt{b^2-4ac})/2a -- this is the usual quadratic formula which you use to solve for for x.
But if you have this one:
{2c}/{-b+-(b^2-4ac)}
Can I also always use this formular for solving? Or is there a different. Can you prove that it doesn't work?
Thanks a lot
Roman