Quadratic Formula applied to 3x^2 - 2x + 4 = 0

[NEHA]

solve by applying the quadratic formula:

3x^2 - 2x + 4 = 0

x = -(-2) +- sqrt( (-2)^2 - 4(3)(4)) / 2(3)

x = 2 +- sqrt( -4 - 4(12)) / 2(3)

x = 2 +- sqrt(-4 - 48) / 2(3)

x = 2 +- sqrt(-52) / 6

i only got up to this:

x = 1/3 +- and i dont know the next number

 

[tkhunny]

First (-2)^2 = +4

Second, you probably want Real solutions. sqrt(negative number) is no good.