quadratic equations..

shefflebat

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Joined
Oct 15, 2005
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3
yeah..i don't exactly get the factor zero product rule. it is confusing. and i have to solve a lot of equations using it, so it would be nice to have a grasp on it..how would i solve something like 3x^2 + 5x = 22 using the factor zero product rule?

completing the square is slightly easier for me to understand, but i still am having trouble solving a lot of equations using it. can someone show me how to solve something like x^2 + 5x = 84 by completing the square?

we aren't supposed to use the quadratic formula, which seems like the easiest way to me..so..yes. some help would definitely be appreciated.
 
The zero product rule just means solving by factoring, ie needs to be placed in the form of (x -4)(x+3)

the solutions rely on each of these being equal to zero (x-4) =0 or (x+3)=0

3x^2 + 5x = 22

3x^2 + 5x - 22 =0

(x......) (x......) = the above

need to have a 3x to make the 3x^2, and look at the factors of 22 = 2 .11

(3x-2)(x+11) ... or ... (3x +11) (x-2)

and you cans see the correct solution is
(3x + 11) (x-2)

then
x^2 + 5x = 84

look at the value in front of the "x" term ie the 5, take 1/2 of this = 2.5

then square the 2.5 value = 2.5 x 2.5 = 6.25

x^2 +5x +6.25 = 84 + 6.25 ie we have added the square to both sides

(x +2.5)^2 = 84 + 6.25

(x +2.5)^2 = 90.25

(x +2.5) = sqrt 90.25

x + 2.5 = + - 9.5

back to you
 
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