Quadratic Equations...

jcmarquez

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Aug 24, 2005
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1. Why do we factor a quadratic equation before we solve it? I think it is to simplyfy to problem but is that the only reason?.
 
By no means is the reason for factoring simplification.
From the axioms for the real field, ℜ, (a)(b)=0 if and only if a=0 or b=0.
Thus x<SUP>2</SUP>−5x+6=0 means (x−2)(x−3)=0 if and only if (x−2)= or (x−3)=0 that is x=2 or x=3.
 
Well, looking at it another way, we TRY to factor a quadratic,
but if that's too difficult, we use the quadratic formula;
so if we're lucky, we've simplified the work...pka??
 
Denis, I not sure of your point??
However, the question is about why factor a quadratic?
The fact is any quadratic with real coefficients can be factored into linear products.
(We may have to use complex numbers).
The solutions are found from the linear factors
 
All I'm trying to say is that it takes less time to solve:
x^2 + x - 2 = 0
than it does to solve:
7x^2 + 3x - 39 = 0

We can easily factor the 1st one; no need to do all the steps
required when the quadratic formula is used.

Not important a point anyway!
 
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