Quadratic Equation

Hockeyman

Junior Member
Joined
Dec 8, 2005
Messages
79
How would you go about simlify this equation?

x^2 = (2x)(x-4)

I got this far

x^2 = 2x(x-4)+2x(x-4)

x^2 = 2x^2 - 8x + 2x^2 - 8x

Now how would you add together the two 2x^2s, would it be 4x^2?

If so, then i came to:

x^2 = 4x^2 -16x

And I'm not sure what to do after that. Thanks for any help in advance.
 
have no clue on what you did ... why are you making it so difficult?

x^2 = (2x)(x-4)
distribute the right side ...
x^2 = 2x^2 - 8x
subtract x^2 from both sides ...
0 = x^2 - 8x
factor ...
0 = x(x - 8)
set each factor equal to 0 and solve ...
x = 0, x = 8

you're done.
 
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