quadratic equation with strange exponents

[schism462]

I am not sure how to even approach this equation. It has exponents that are a bit odd and I'm not even sure how to begin.

I must find all real solutions for this problem.


x^2/3-2x^1/3-15=0

No decimals allowed.We have to put them in terms with whole numbers, radicals, i, or fractions.

 

[tkhunny]

Well, do it! What differences does the appearance of the exponent make? As lone as one is the square of hte other, you're in business.


\(\displaystyle x^{2/3} - 2x^{1/3} - 15 = (x^{1/3} - 5)(x^{1/3} + 3) = 0\)


Now what?