quadratic equation: t^2 + 1 = 13/6t

G

Guest

Guest
t^2 + 1 = 13/6t

so far I have:

t^2 - 13/6t + 1 = 0

then:

6t^2 - 78t + 6 = 0

Am I on the right track, what next, please help
 
Re: homework help-quadratic equation

Caron said:
6t^2 - 78t + 6 = 0
Click to expand...
Not quite.

Why did you pick '6'? It is very important that you understand WHY you picked that value. If you do, you never will make that mistake again.
 
quadradic equation

I was trying to get rid of the denominator of 6 by multiplying all by 6 for even distribution of 6 to make it go away.
HELP
Caron
 
\(\displaystyle \L
6\left( {\frac{{13}}{6}} \right) = 13\)
 
Re: quadradic equation

Caron said:
I was trying to get rid of the denominator of 6 by multiplying all by 6 for even distribution of 6 to make it go away.
HELP
Caron
Click to expand...
Exactly. Once you used the '6' to make the '6' in the denominator go away, why did you use the '6' AGAIN to multiply by the 13? ;-) Only one per customer.

Personally, I wouldn't even think about that term. I picked the '6' to clean up the denominator, so simply write that term with the denominator cleaned up. Why mess with it?
 
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