Quadratic equation - help

[mcruz65]

h=16t^2+vt+s
h-h=16t^2+vt+s-h
0=16t^2+vt+s-h
a=16,b=v,c=s-h
t=(-b±?(b^2-4ac))/2a
t=(-v±?((v)^2-4(16)(s-h) ))/2(16)
t=(-v±?(v^2-4(16s-16h) ))/32
t=(-v±?(v^2-64s+64h))/32
t=(-v±v+8s+8h)/32
t=(-v±)/32 v/32+8s/32+8h/32 **This is where I get stuck. Please help.**

 

[arthur ohlsten]

t= {-v+/-[v^2-64(s-h)]^1/2 /32 the next step is in error

[v^2-64(s-h)] take sqrt
[v - 8 sqrt(s-h)] [v+8 sqrt(s-h)]

The solution for t will have 2 answers, but each answer will be in terms of v,s,and h,Unless you have values for them
Arthur

 

[Denis]

h=16t^2+vt+s

WHAT are you asked to do with this equation?
Perhaps to solve for t if h=0 ?
When posting a problem, please post it in full, in it's original form.

 

[mcruz65]

So sorry. Yes it is to solve for t. Also I know that the solution for t will have two answers. I need some guidance on how to proceed.

 

[wjm11]

h=16t^2+vt+s
h-h=16t^2+vt+s-h
0=16t^2+vt+s-h
a=16,b=v,c=s-h
t=(-b±?(b^2-4ac))/2a
t=(-v±?((v)^2-4(16)(s-h) ))/2(16)
t=(-v±?(v^2-4(16s-16h) ))/32
t=(-v±?(v^2-64s+64h))/32

You are correct up to here. STOP HERE. This is your answer. (If you are given values for v, s, and h, you can plug them in and evaluate.)

Your next step was wrong:

t=(-v±v+8s+8h)/32

You cannot take the square roots of the individual terms that way.

 

[mcruz65]

Thank you for your help.