Quadratic Equation Approach

[Muffins]

I was wondering if this is the right way to solve this:

 

[Deleted member 4993]

I was wondering if this is the right way to solve this:

In the third step you should write:

\(\displaystyle \pm (2x) \ = \ 10(2-x)\)

2x = 10(2-x) ............or.............. -2x = 10(2-x)

2x = 20 - 10x ...........or.............. -2x = 20 - 10x

12x = 20 ................or.............. 8x = 20

and you get two values for 'x'.

Don't forget to check your answer by putting your answer back into the original equation.