Q on sqrts and sequences: sqrt(2 + sqrt(4 + ...))

tomas_xc

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Feb 22, 2008
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Can somebody help me solve this expression?
sqrt( 2 + sqrt( 4 + sqrt( 8 + sqrt( 16 + sqrt( 32 + ... sqrt( 2^2008))))))
 
It's not really striking me how to SIMPLIFY the expression. If it were infinite, it would be easier.

If
\(\displaystyle \sqrt{2+\sqrt{4+\sqrt{8+...}}} = x\)
then
\(\displaystyle \sqrt{2+\sqrt{4+2\sqrt{2+\sqrt{4+\sqrt{8+...}}+...}}} = x\)
and
\(\displaystyle \sqrt{2+\sqrt{4+2x}} = x\)
That's not too hard to solve for the four Real solutions. Obviously, only the positive one would be useful.

Perhaps it will lead ot something for your finite case.
 
If it were infinite, it would be easier.

I don't believe it'll make much difference. It may has well be infinite as to have 2^2008 power.

I believe your case is the ticket, TKH.
 
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