Q about functions: Suppose f(x) = ax. Describe the graph of

[micheleab]

Suppose that f(x)=ax [where a cannot equal 0]

a. Describe the graph of y=f(x) ---> I am not able to enter this into my graphing calculus.

b. Explain why [the f inverse of X] F-1(x) contains the origin---> what would this equation be and what do they mean by the origin.

could you please explain these answers to me...I am not looking to just copy down the answers..im looking to understand it.

 

[galactus]

ax would be a line. The origin is just what it says. The origin of the graph, (0,0). Since a line has equation y=mx+b, where b is where it crosses the y-axis, the line must pass through the origin because b=0. Hence, y=ax.
a is the slope.

For the inverse, just switch the x and y around and solve for y.

y=ax

x=ay, solve for y.

You don't have to do that to see the inverse of a is 1/a.