Pythagorean Theorem help

Timcago

Junior Member
Joined
Apr 13, 2006
Messages
77
The length of the hypotenuse of a right triangle is 3 less than 4 times the length of the shortest leg. The length of the other leg is 3 more than 3 times the length of the shortest leg. What are the lengths of all 3 sides?

My progress.

Let a represent the length of the shortest side. Let b represent the length of the second shortest side. let c represent the length of the hypotenuse.

c=4a-3, b=3a+3

a^2=c^2-b^2

a^2=(4a-3)^2-(3a+3)^2

a^2=(16a^2-24a+9)-(9a^2+18a+9)

a^2=7a^2-42a

a= (7a(a-6))^(1/2)

Did i do soemthing wrong? How do i find the value of a and how do i find the lengths of each side.
 
Timcago said:
The length of the hypotenuse of a right triangle is 3 less than 4 times the length of the shortest leg. The length of the other leg is 3 more than 3 times the length of the shortest leg. What are the lengths of all 3 sides?

My progress.

Let a represent the length of the shortest side. Let b represent the length of the second shortest side. let c represent the length of the hypotenuse.

c=4a-3, b=3a+3

a^2=c^2-b^2

a^2=(4a-3)^2-(3a+3)^2

a^2=(16a^2-24a+9)-(9a^2+18a+9)

a^2=7a^2-42a

a= (7a(a-6))^(1/2)

Did i do soemthing wrong? How do i find the value of a and how do i find the lengths of each side.

a^2=7a^2-42a...

6a^2 - 42a = 0
a(6a - 42) = 0

then either a=0 or 6a-42=0. It is obvious that a is not zero, so:

6a-42 = 0
6a = 42, a = 7

b=3(7)+3 = 24
c=4(7)-3 = 25

check: 25^2 = 24^2 + 7^2
625 = 576 + 49.
yup.
 
Top