Pyramid / Tetrahydron

[InterserveVB]

Find the volume of a pyramid with a height of 9 and a triangular equalateral base with sides of 8

 

[pka]

Given an equilateral triangle with length of a side s then
\(\displaystyle Area = \left( {1/2} \right)\left( {s^2 } \right)\sin (\pi /3)\).

 

[InterserveVB]

The base is equalateral. The high is diffrent from the sides of the base. The bottom is a triangle with sides of length 8. The sides of the object are also triangles but they are not equalateral the overall height is 9. I tried the setup you possed and didn't get the answer in the back of the book. It should be about 83.14. I am sorry if my wording before was a bit vague.

 

[pka]

The volume of a pyramid is \(\displaystyle \frac{h}{3}\left( {Area} \right)\).
When I do that I get the same answer as your textbook.