Pump

johnjones

New member
Joined
Sep 8, 2005
Messages
41
I have no idea how to start or do this.

If pump A can empty the pool in 20 minutes, and pump B can empty in 30 minutes, how long should it take if both pumps are used?

Thanks.
I don't even know (was not given) values.. i.e. volume of pool and that stuff.
 
The secret is to figure what fraction is emptied in one minute. Just to illustrate, say one takes 6 minutes and the other takes 4 minutes. One pump empties 1/6 in one minute and the other empties 1/4 in one minute. Together they would empty 1/6 + 1/4 = 10/24 in one minute. So it would take both 24/10 = 2.4 minutes.
1/A+1/B=1/X
Study this and apply it to your problem.
 
Hello, johnjones!

Gene is absolutely correct . . . Here's another approach.

If pump A can empty the pool in 20 minutes, and pump B can empty in 30 minutes,
how long should it take if both pumps are used?
Let x = number of minutes for both pumps to empty the pool.

Pump A takes 20 minutes to empty the pool.
. . In one minute, it empties 1/20 of the pool.
. . In x minutes, it empties x/20 of the pool (some fraction of the pool).

Pump B takes 30 minutes to empty the pool.
. . In one minute, it empties 1/30 of the pool.
. . In x minutes, it empties x/30 of the pool (another fraction of the pool).

Together, in x minutes, they empty the entire pool ("1 pool").

. . . . . . . . . . . . . . . . . . . . x . . . x
There is our equation: . ---- + --- . = . 1
. . . . . . . . . . . . . . . . . . . 20 . . 30
 
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