fatherjack
New member
- Joined
- Aug 19, 2013
- Messages
- 2
33 ms = 33 x 10-3 s = 0.033 s
So, the duty cycle is (0.033 s ÷ T s) x 100% = 3%
(what is the value of T)
Transposing the formula gives T s = insert your workings here =
= Ans A s
= Ans B ms
1 hour = 60min x 60 s = 3 600 s
So, in 1 hour the node transmits,
3 600 s = Ans C times
Ans A s
Therefore, node transmits for
0.033 s x Ans C =
= Solution (3 s.f.) in every hour
So, the duty cycle is (0.033 s ÷ T s) x 100% = 3%
(what is the value of T)
Transposing the formula gives T s = insert your workings here =
= Ans A s
= Ans B ms
1 hour = 60min x 60 s = 3 600 s
So, in 1 hour the node transmits,
3 600 s = Ans C times
Ans A s
Therefore, node transmits for
0.033 s x Ans C =
= Solution (3 s.f.) in every hour