proving e^(x-y) = (e^x)/(e^y)

[sonzai]

I don't understand how to prove the law of exponents using the laws of logarithm...:
e^(x-y) = (e^x)/(e^y)
I'm hoping someone can help...
thanks in advance!

 

[o_O]

You can take the natural logarithm of both sides and see what you get.