Prove that there exists n ∈ N that: 1357^n has the end is ..0...0001 ( 2017 number 0)
Hello everyone, I'm new here. I have a discrete math class and I'm not good at math. Please help me with this question, I'm totally clueless and don't know where to start. The question is : Prove that there exists n ∈ N that: 1357^n (1357 exponent n) has the end is ..0...0001 ( 2017 number 0)
Please help me, I need a clue so that I know where to start at least. Thank you all and I'm sorry for any mistakes, I'm not a native English speaker
Hello everyone, I'm new here. I have a discrete math class and I'm not good at math. Please help me with this question, I'm totally clueless and don't know where to start. The question is : Prove that there exists n ∈ N that: 1357^n (1357 exponent n) has the end is ..0...0001 ( 2017 number 0)
Please help me, I need a clue so that I know where to start at least. Thank you all and I'm sorry for any mistakes, I'm not a native English speaker