n=5k+2l=2*2k+k+2l=k+2(l+2k). Choosing l=-2k , then we have n=k. Thus for every n there are k,l such that n=5k+2l (there is at least one pair of them: k=n and l=-2k=-2n). The question is how many are the possible pairs (as a function of the integer)?
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