Re: antiderivative help
Hmm, you're asked to prove something but all you're given an integral to find.
Anyhow, this is a pretty standard integral:
\(\displaystyle \int secx dx = ln (secx + tanx) + C \quad \quad \mbox{(Those should be absolute value signs)}\)
The trick is to multiply secx by (secx + tanx) / (secx + tanx) and perform the appropriate u-substitution.
\(\displaystyle \int secx dx = \int secx \cdot \frac{secx + tanx}{secx + tanx} dx\)
And so on.