Proportions Help

Fragile Dreams

New member
Joined
Dec 17, 2005
Messages
45
Okay, here's the question:

<< Jose Balboa left his office at 12.00 noon, and by 3.00 PM he had driven 126 of the 189 miles between his office and the office of a client. If he continues driving at the same speed, at what time could he expect to arrive at the client's office? >>

So far, this is what I have:

126
___

189

and

3
___

X

[ 126 mi to 189 mi] · [3 hrs to x hrs]

I'm not quite sure if the proportions are correct, so I would appreciate some insight!
 
Fragile Dreams said:
Okay, here's the question:

<< Jose Balboa left his office at 12.00 noon, and by 3.00 PM he had driven 126 of the 189 miles between his office and the office of a client. If he continues driving at the same speed, at what time could he expect to arrive at the client's office? >>

So far, this is what I have:

126
___

189

and

3
___

X

[ 126 mi to 189 mi] · [3 hrs to x hrs]

I'm not quite sure if the proportions are correct, so I would appreciate some insight!
\(\displaystyle \L \mbox{\frac{129}{189} = \frac{3}{x}}\) ,where \(\displaystyle \mbox{x}\) is the total time of the journey in hours, is correct. Solve for \(\displaystyle \mbox{x}\).


Don't forget to translate the travel time (\(\displaystyle \mbox{x}\)) into a clock time.
 
problem

Okay, his speed is 126 miles/3 hours , right?
And , and he likes (189-126) = 63 more miles to go.
To find out how long it would take to go 63 miles, set up ratio: 126 miles/3 hours = 63 miles/ x hours, and find x.
So, 126x = 3*63, so x = (3*63)/126 = 1.5 hours.
So, all together, it would take him 3 + 1.5 = 4.5 hours!
 
Fragile Dreams said:
Alright, just checking. Thanks.
To have the tutors check your work and/or your answers, please include them in your posts.

Thank you.

Eliz.
 
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