Hi, are the following steps valid?
Case 1 :
P = (1+t)S
lnP = ln(1+t) + lnS ( taking natural log )
dlnP = dln(1+t) + dlnS ( where d stands for small differential )
Case 2 :
P = (1+t)S
dP = d[(1+t)S] ( where d stands for small differential )
dP = d(1+t)dS
Case 1 :
P = (1+t)S
lnP = ln(1+t) + lnS ( taking natural log )
dlnP = dln(1+t) + dlnS ( where d stands for small differential )
Case 2 :
P = (1+t)S
dP = d[(1+t)S] ( where d stands for small differential )
dP = d(1+t)dS