Proofs:HOW DO YOU DO PROOFS INVOLVING PERPENDICULAR BISECTOR

[sportychick9890]

GIVEN: SEGMENT MN IS CONGRUENT TO SEGMENT MP; <NMO IS CONGRUENT <PMO

PROVE:LINE MO IS THE PERPENDICULAR BISECTOR OF SEGMENT NP.

N
:
:
M---------Q------------O
:
:
P

MN IS CONNECTED NO, PO,AND MP TO.









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[sportychick9890]

NP IS SUPPOSED TO BE IN THE MIDDLE SORRY

 

[stapel]

NP IS SUPPOSED TO BE IN THE MIDDLE SORRY

Do you mean something along the lines of the following?

          N
          |
          |
          |
M---------Q---------O
          |
          |
          |
          P

Please confirm or correct.

MN IS CONNECTED NO, PO,AND MP TO.

I'm sorry, but I have no idea what this is supposed to mean.

Please reply with the complete and exact text of the exercise, and a listing of the steps and reasoning you have attempted thus far. Complete sentences will be helpful. Thank you.

Eliz.

 

[sportychick9890]

YES, THAT'S CORRECT. IN ADDITION THE SIDE ARE ALL CONNECTED I JUST DIDN'T KNOW HOW TO DRAW IT.

 

[stapel]

I JUST DIDN'T KNOW HOW TO DRAW IT.

As demonstrated, use the "code" tags, and check your work (often repeatedly -- trust me on this) using the "Preview" button before posting.

IN ADDITION THE SIDE ARE ALL CONNECTED

Please clarify what you mean by a "side" being connected. Which side? And to what? Drawing a picture (or editing the one provided) might be helpful as well.

Thank you.

Eliz.

 

[soroban]

Re: Proofs:HOW DO YOU DO PROOFS INVOLVING PERPENDICULAR BISE

Hello, sportychick9890!

Some friendly advice:
\(\displaystyle \;\;\)Take off the Shift Lock.
\(\displaystyle \;\;\)Click "Preview" befor you "Submit"

Given: \(\displaystyle \overline{MN}\,=\,\overline{MP}.\;\angle NMO\,=\,\angle PMO\)

Prove: \(\displaystyle \overline{MO}\) is the perpendicular bisector of \(\displaystyle \overline{NP}\).

            N
            *
           /| \
          / |   \
         /  |     \
      M * - + - - - * O
         \  |Q    /
          \ |   /
           \| /
            *
            P

\(\displaystyle 1.\;MN\,=\,MP\). . . . . . . . . . . . . . \(\displaystyle 1.\text{ Given}\)

\(\displaystyle 2.\;\angle NMO\,=\,\angle PMP\). . . , . . . \(\displaystyle 2.\text{ Given}\)

\(\displaystyle 3.\;NQ\,=\,NQ\). . . . . . . . . . . . . . . \(\displaystyle 3.\text{ Reflexive postulate}\)

\(\displaystyle 4.\;\Delta MON\text{ congr }\Delta MOP\). . . \(\displaystyle 4.\text{ s.a.s.}\)


Now we have: \(\displaystyle \,NQ\,=\,PQ\;\;\Rightarrow\;\;MO\text{ bisects }NP\)

and \(\displaystyle \,\angle MQN\,=\,\angle MQP\;\;\Rightarrow\;\;\angle MQN\,=\,90^o\;\;\Rightarrow\;\;MO\,\perp\,NP\)

I'll let you supply the reasons . . .