Proof with no figure! What?

[Guest]

The measure of a line segment, PC, I to hypotenuse, AC of right triangle ABC, is equal to the measure of leg, BC. Show BP may be I or parallel to the bisector of angle A.

Thanks

 

[Denis]

The measure of a line segment, PC, I to hypotenuse, AC of right triangle ABC, is equal to the measure of leg, BC. Show BP may be I or parallel to the bisector of angle A. Thanks

[geezzzzzz...is it me...]
WHAT'S an "I to hypotenuse" ????????????

 

[Guest]

The measure of a line segment, PC, I to hypotenuse, AC of right triangle ABC, is equal to the measure of leg, BC. Show BP may be I or parallel to the bisector of angle A. Thanks

[geezzzzzz...is it me...]
WHAT'S an "I to hypotenuse" ????????????

That would be helpful to know... Clarify that please Bradley?

 

[soroban]

Hello, asbradley85!

I guess you aren't too anxious for the solution.
. . You haven't checked back.

I haven't solved the problem, but I think I understand the problem.

See what you think, Denis and Andrew . . .

The measure of a line segment, PC, I to hypotenuse, AC of right triangle ABC,
is equal to the measure of leg, BC. Show BP may be I or parallel to the bisector of angle A.

Evidently on Bradley's planet, "I" means "perpendicular to".

   A
   *                  
   | \               P       PC is perpendicular to AC.
   |   \           *                    PC = BC.
   |     \       /           Prove: BP is perpendicular
   |       \   /             to  the bisector of angle A.
   * - - - - *
   B         C



   A
   *                         PC is perpendicular to AC.
   | \                                 PC = BC.
   |   \                     Prove: BP is parallel to
   |     \                   the bisector of angle A.
   |       \
   * - - - - *C
   B        /
          /
        *
      P

It seems to make sense . . . and eyeballing it, it looks reasonable.
. . . now I need a proof.

 

[Guest]

I apologize for not checking back. But I does mean perpendicular. I was trying to underline the I i guess that didn't work.

Thanks