Proof using contradiction: If x <= y+c for c > 0 then x <= y

[vikramtiwari]

Let x, y be real numbers such that x<= y+c for every c>0. Then x<=y. Prove this by contradiction....

 

[stapel]

A good start might be to write down the statement you'll use to begin the contradiction proof. :wink:

Eliz.

 

[pka]

Suppose that \(\displaystyle y < x\).
Then \(\displaystyle c = \frac {x - y}{2} > 0\).
Use that in the given.