Assume that, for some k, \(\displaystyle 2^k> k+ 4\). Then \(\displaystyle 2^{k+1}= 2(2^k)> 2(k+ 4)= 2k+ 8\).
Now you need to show that \(\displaystyle 2k+ 8> (k+1)+4= k+ 5\). That looks very easy.
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