renolovexoxo
New member
- Joined
- Mar 31, 2012
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- 13
Critique the following proof of the triangle inequality for real numbers x and y (|x+y|</=|x|+|y|)
When x and y are both non-negative, both sides equal x+y. When x and y are both non-positive, both sides equal -x-y. When x and y have opposite signs, we may assume that x>0>y. The inequality then holds because
|x+y|=max{x+y,-x-y}<x-y=|x|+|y|
I tried a critique twice and both times my teacher said I was wrong. Any help?
When x and y are both non-negative, both sides equal x+y. When x and y are both non-positive, both sides equal -x-y. When x and y have opposite signs, we may assume that x>0>y. The inequality then holds because
|x+y|=max{x+y,-x-y}<x-y=|x|+|y|
I tried a critique twice and both times my teacher said I was wrong. Any help?