megadeth95
New member
- Joined
- Nov 25, 2011
- Messages
- 35
Hello guys, I'm having difficulties with the following problems. I would really appreciate your help.
A) you have a necklace and a bracelet with two types of beads. There are 30 small beads and 6 large beads on the necklace. The bracelet has 10 small beads and 2 large beads. The necklace weighs 3.6 grams and the bracelet weighs 1.2 grams. If the necklace has no significant weight, find the weight of one large bead.
Ok, this is what I did so far:
x = weight of small bead
y = weight of large bead
Necklace -------- 30x + 6y = 3.6
Bracelet --------- 10x + 2y = 1.2
After setting up the 2 equations, I used the elimination method to eliminate y. However, when I solve for x, the answer I get is 0
B) You and nine friends have decided to spend $50 in the amusement park. Bumper cars cost $3 per hour and two people can ride in each car. Another choice is the water slide. The cost is $8 per person.
1) Write an equation that shows how many bumper car tickets (b) and water slide passes (w) you would need to purchase.
2)Write an equation that expresses how much the bumper car tickets and water slide passes would cost and remain within the confines of your recreational budget.
3)according to the equations in 1 and 2, how many bumper cars and water slide passes can you purchase?
This is what I did so far:
1) b = bumper cars
w = water slide
2b + w = 10
I put 2 b/c it says that "two people can ride in each car", Is this correct???
2) 3b + 8w = 50
3) 2b + w = 10
3b + 8w = 50
----------------
-8 (2b + w = 10)
3b + 8b = 50
------------------
- 16b - 8w = -80
3b +8b = 50
------------------
-13b = -30
b = 2.07 ( Is this correct???)
Please guys, let me know if I did something wrong
Thank you very much
A) you have a necklace and a bracelet with two types of beads. There are 30 small beads and 6 large beads on the necklace. The bracelet has 10 small beads and 2 large beads. The necklace weighs 3.6 grams and the bracelet weighs 1.2 grams. If the necklace has no significant weight, find the weight of one large bead.
Ok, this is what I did so far:
x = weight of small bead
y = weight of large bead
Necklace -------- 30x + 6y = 3.6
Bracelet --------- 10x + 2y = 1.2
After setting up the 2 equations, I used the elimination method to eliminate y. However, when I solve for x, the answer I get is 0
B) You and nine friends have decided to spend $50 in the amusement park. Bumper cars cost $3 per hour and two people can ride in each car. Another choice is the water slide. The cost is $8 per person.
1) Write an equation that shows how many bumper car tickets (b) and water slide passes (w) you would need to purchase.
2)Write an equation that expresses how much the bumper car tickets and water slide passes would cost and remain within the confines of your recreational budget.
3)according to the equations in 1 and 2, how many bumper cars and water slide passes can you purchase?
This is what I did so far:
1) b = bumper cars
w = water slide
2b + w = 10
I put 2 b/c it says that "two people can ride in each car", Is this correct???
2) 3b + 8w = 50
3) 2b + w = 10
3b + 8w = 50
----------------
-8 (2b + w = 10)
3b + 8b = 50
------------------
- 16b - 8w = -80
3b +8b = 50
------------------
-13b = -30
b = 2.07 ( Is this correct???)
Please guys, let me know if I did something wrong
Thank you very much