There are two pairs (x,y) of real numbers that satisfy the equation X+y=3xy=4. Given that the solutions x are in the form a+- (b *sqrt c)/ d. Where a, b, c, e are integers and the expression is completely simplified , what is the value of a+b+c+d
There are two pairs (x,y) of real numbers that satisfy the equation X+y=3xy=4. Given that the solutions x are in the form a+- (b *sqrt c)/ d. Where a, b, c, e are integers and the expression is completely simplified , what is the value of a+b+c+d
As written, you have TWO equations in two unknowns:
\(\displaystyle x + y = 4 \)
\(\displaystyle 3\ x\ y = 4 \)
One way to solve would be to eliminate \(\displaystyle y\) by substituting it from the first equation into the second equation.
That gives a quadratic equation for \(\displaystyle x\). Does that get you going?
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