babadany2999
New member
- Joined
- Jun 9, 2020
- Messages
- 6
Hello so I am self teaching calculus atm(almost end of calc1) and i've encountered a bunch of problems where i need to know the value of angle x given a trig function like cosx = a , a some number. I've looked for an answer the first time i encountered this but i couldn't find it. So now again i encountered one more problem like this and i need to know all of the values of x where cos x = -1/2, 0 <= x <= 2pi (it's actually an example but again my thinking is not the same as what actually is in the book).
My thinking is that cosine is negative in quadrant 2,3.Since we have cos x = 1/2 at x = pi/3 or at 60* then we should have the negative value(-1/2) at pi/3 + pi/2 (60*+90*) or 5pi/6 . And at pi + pi/3 = 4pi/3 . But in the book it says 2pi/3 and 4pi/3 . I do not understand why this is it...so please help if you can(and sorry for the noob question)
My thinking is that cosine is negative in quadrant 2,3.Since we have cos x = 1/2 at x = pi/3 or at 60* then we should have the negative value(-1/2) at pi/3 + pi/2 (60*+90*) or 5pi/6 . And at pi + pi/3 = 4pi/3 . But in the book it says 2pi/3 and 4pi/3 . I do not understand why this is it...so please help if you can(and sorry for the noob question)