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3 people had a bag of apples. While two of them were sleeping one of them ate 1/3 of the apples. Later a second person ate 1/3 of those remaining apples. Finally the third person ate 1/3 of those remaining apples, leaving 8 apples in the bag. How many apples were in the bag originally?
 
Is this all the information? Did they not give you the amount left over after the third person ate some?

Eliz.
 
In another thread said:
3 people had a bag of apples. While two of them were sleeping one of them ate 1/3 of the apples. Later a second person ate 1/3 of those remaining apples. Finally the third person ate 1/3 of those remaining apples, leaving 8 apples in the bag. How many apples were in the bag originally?
You are given that eight were left after eating one-third of the remaining apples. Then "8" is two-thirds of what had remained. What number is 8 two-thirds of? (Hint: Divide eight into two parts. Add one part to the two parts, for three parts. The 8 was two-thirds of the three parts, and the sum of the three parts was the number that 8 was two-thirds of.)

Follow backwards through the steps, using this logic, until you get back to the original amount.

Eliz.
 
Hello, Brittany Bache!

3 people had a bag of apples.
While two of them were sleeping one of them ate 1/3 of the apples.
Later a second person ate 1/3 of those remaining apples.
Finally the third person ate 1/3 of those remaining apples, leaving 8 apples in the bag.
How many apples were in the bag originally?
Let \(\displaystyle N\) = number of apples in the bag originally.

After the first person ate, there were \(\displaystyle \frac{2}{3}N\)apples left.

After the second person ate, there were \(\displaystyle \frac{2}{3}\,\times\,\frac{2}{3}N \,=\,\frac{4}{9}N\)apples left.

After the third person ate, there were \(\displaystyle \frac{2}{3}\,\times\,\frac{4}{9}N\,= \,\frac{8}{27}N\)apples left.

. . But we are told that there were 8 apples left.

There is our equation! . . . . \(\displaystyle \frac{8}{27}N = 8\qquad\Rightarrow\qquad N = 27\)
 
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