G
Guest
Guest
What are three number that are even, have one 7 in the numeral; the sum of the tens and units digit is divisible by 5; and the hundreds digit is greater then the units digit; which is greater than the tens digit.
You are using an out of date browser. It may not display this or other websites correctly.
You should upgrade or use an alternative browser.
You should upgrade or use an alternative browser.
They are even so the units digits are 0,2,4,6 or 8
The units digits are greater than the tens none is 0
If you look at all the possiblities there are four sets that add to a multiple of 5 that could be the units digits.
2 2 6
2 4 4
4 8 8
6 6 8
If the units digit is 8 then the hundreds is 9 so that number is 978
The 488 group gives
978
978
714
The units digits are greater than the tens none is 0
If you look at all the possiblities there are four sets that add to a multiple of 5 that could be the units digits.
2 2 6
2 4 4
4 8 8
6 6 8
If the units digit is 8 then the hundreds is 9 so that number is 978
The 488 group gives
978
978
714
Hello, Brittany!
Since the number is even, the "7" must be T or H..
If T = 7, then U = 8, H = 9.
. . One answer: 978
Suppose H = 7.
Since U is even, and U + T = 5k, and U > T,
. . we have only: .U = 4, T = 1 and U = 6, T = 4.
Two more answers: 714, 746.
Let H = hundreds digit, T = tens digit, U = units digit.What are three numbers that are even, have one 7 in the numeral;
the sum of the tens and units digit is divisible by 5;
and the hundreds digit > the units digit > the tens digit.
Since the number is even, the "7" must be T or H..
If T = 7, then U = 8, H = 9.
. . One answer: 978
Suppose H = 7.
Since U is even, and U + T = 5k, and U > T,
. . we have only: .U = 4, T = 1 and U = 6, T = 4.
Two more answers: 714, 746.