problem involving logaritmic function

[shweta]

please help me in this, i dont know how to start

If A=log₂log₂log₄ 256 + 2 log_*2², then A= ?? (* means square root)

The answer is 5, but i didnt get it..

 

[srmichael]

please help me in this, i dont know how to start

If A=log₂log₂log₄ 256 + 2 log_*2², then A= ?? (* means square root)

The answer is 5, but i didnt get it..

I assume you meant:

\(\displaystyle A=\log_{2}(\log_{2}(log_{4}256))+2\log_{\sqrt{2}}(2)?\)

That being said, what are some of the basic log rules you have learned?

 

[srmichael]

SR, methinks you need brackets around the last "2";
quick....before lookagain gets a hold of you

Phew! Thanks! That was a close one!!

 

[shweta]

I assume you meant:

\(\displaystyle A=\log_{2}(\log_{2}(log_{4}256))+2\log_{\sqrt{2}}(2)?\)

That being said, what are some of the basic log rules you have learned?

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THANKYOU SO MUCH!! I got it!!
we can do this easily like log₄256 = 4 log₄4 = 4. Similarliy, we can simplify the whole thing, adding brackets makes it easier to understand quickly..