Seimuna said:erm...then how to rewrite it into double integral ? & how to switch the order of integration ?
Subhotosh Khan said:This is an integral of summation functions with single variable - where is double integral coming from?
Seimuna said:Evaluate \(\displaystyle \int_{0}^{1} [arcsin [2-x]]-[arcsin [x]] dx\) by rewriting it as double integral and switching the order of integration.
Seimuna said:Evaluate \(\displaystyle \int_{0}^{1} [arcsin [2*x]]-[arcsin [x]] dx\) by rewriting it as double integral and switching the order of integration.
Seimuna said:Evaluate \(\displaystyle \int_{0}^{1} [arcsin [2*x \, - \, 1]]-[arcsin [x]] dx\) by rewriting it as double integral and switching the order of integration.
Subhotosh Khan said:The problem would make sense - if the statement was:
Seimuna said:Evaluate \(\displaystyle \int_{0}^{1} [arcsin [2*x]]-[arcsin [x]] dx\) by rewriting it as double integral and switching the order of integration.
Now it would be area contained between two lines and can be converted to double integral.
[/quote]Seimuna said:Evaluate \(\displaystyle \int_{0}^{1} [arcsin [2*x \, - \, 1]]-[arcsin [x]] dx\) by rewriting it as double integral and switching the order of integration.