problem help

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Jun 5, 2013
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three workers sort 66 boxes in a day one of the workers is three times more productive than the second worker and twice as productive as the third how many boxes did the second most productive worker sort ?
 
Let x be the unit for amount of work done. Since one worker works twice as hard as another and thrice as hard as the last, we have

\(\displaystyle 6x+3x+2x=66\).

Solving for x gives x=6, so the amount of boxes packed for the workers is 12, 18, and 36. The second most efficient worker packs 18 boxes a day.
 
Let x be the unit for amount of work done. Since one worker works twice as hard as another and thrice as hard as the last, we have

\(\displaystyle 6x+3x+2x=66\).

eddybob123, please don't jump right in and do all the work for the asker. \(\displaystyle \ \ \ \ \ \ Rules \ \ for \ \ posting: \ \ \)http://www.freemathhelp.com/forum/threads/54003-Read-Before-Posting
 
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