Problem Checking The Solution.

[SCSmith]

25-4u/3 = 5u+12/4 +6 = -8/31 That is the correct solution. I have a problem checking the problem with the solution. Here are my calculations.

25-4(-8/31) 5(-8/31)+12 25+32/31 5(364/31)
-------------- = ----------------- +6 = ------------- = ----------- + 6 =
3 4 3 4


807/31 = 1820/31 4(807/31) 3(1820/31) 3228/31 5460/31
--------- ---------- = ----------- = ------------- = --------- = ---------
3 4 12 12 12 12

This is as far as I get.
How come when I carefully write out the problem it comes out all confused and unedited when I hit the submit button?

 

[galactus]

You can use

 to keep it from getting scrambled. Better yet, learn LaTex.

 

[soroban]

Hello, SCSmith!

First of all, write what you mean.

"25-4u/3 = 5u+12/4 +6 = -8/31" makes no sense.

Some parentheses and spaces would certainly help us.
I assume you mean: (25 - 4u)/3 = (5u + 12)/4

Then what is that -8/31 on the end?
Oh, I get it . . . that's the answer!
Start a new sentence: u = -8/31.

If you looked at your stuff before you posted it,
. . you'd have seen that spaces are not preserved.
You can type "x . y", but it will come out xy.

And you have far too many equal-signs in your work.
At the end of each equation, take a breath and start a new one! **


We have: \(\displaystyle \L\:\frac{25\,-\,4u}{3}\;=\;\frac{5u\,-\,12}{4}\,+\,6\;\;\) and we will check: \(\displaystyle x\,=\,-\frac{8}{31}\)


Now, don't write an equation . . . We going to prove that the two sides are equal.

The left side is: \(\displaystyle \L\:\frac{25\,-\,4(-\frac{8}{31})}{3} \;=\;\frac{25\,+\,\frac{32}{31}}{3} \;= \;\frac{\frac{807}{31}}{3} \;=\;\fbox{\frac{269}{31}}\)

The right side is: \(\displaystyle \L\:\frac{5(-\frac{8}{31})\,+\,12}{4}\.+\.6 \;= \;\frac{-\frac{40}{31}\,+\,12}{4}\,+\,6\)

. . . . \(\displaystyle \L=\;\frac{\frac{332}{31}}{4}\,+\,6 \;=\;\frac{83}{31}\,+\,6\;=\;\fbox{\frac{269}{31}}\)


There! . . . They are equal!

~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~

**

Suppose your teacher wrote this on the board: .2x+3=9=2x=6=3

Would you have a clue about what he's talking about? .(6 = 3 ?)
. . So you ask him what it says.

And he says, "What's the matter with you? .It's so obvious!

. . . . . . . . . . . . . We have: \(\displaystyle \,2x\,+\,3\:=\:9\)

Subtract 3 from both sides:. . . \(\displaystyle \,2x \:=\:6\)

. Divide by both sides by 2: . . . \(\displaystyle \,x\:=\:3\) "

After you say, "Then why didn't you write it that way?",
. . you'd have him arrested for impersonating a human being.