problem about almost sure convergence

yavanna

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Nov 11, 2009
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Does (Xn)n1\displaystyle (X_{n})_{n_{\geq 1}}, Xn=nln(n)Yn\displaystyle X_{n}=\frac{n}{ln(n)}Y_{n}, where YnExp(n)\displaystyle Y_{n} \sim Exp(n) converge a.s. to 0?
 
As n goes to zero, for n rational, this converges on 0,
but surely you mean for n natural.
if n>1, the function diverges, as n increases,
if Y = e[sup:152he7pm]-n[/sup:152he7pm], the function converges on zero as n increases.
 
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