Is it correct method?
D Deleted member 4993 Guest Aug 23, 2021 #2 chandra21 said: Is it correct method? View attachment 28635 Click to expand... This is excellent for an answer in a test. For homework, I would add: a2xy + b2xy + abx2 + aby2 = a2xy + abx2 + aby2 + b2xy = ax*(ay + bx) + by*(ay + by) = (ay + bx) * ( ax + by)
chandra21 said: Is it correct method? View attachment 28635 Click to expand... This is excellent for an answer in a test. For homework, I would add: a2xy + b2xy + abx2 + aby2 = a2xy + abx2 + aby2 + b2xy = ax*(ay + bx) + by*(ay + by) = (ay + bx) * ( ax + by)
chandra21 Junior Member Joined May 23, 2013 Messages 66 Aug 23, 2021 #3 Subhotosh Khan said: View attachment 28636 This is excellent for an answer in a test. For homework, I would add: a2xy + b2xy + abx2 + aby2 = a2xy + abx2 + aby2 + b2xy = ax*(ay + bx) + by*(ay + by) = (ay + bx) * ( ax + by) Click to expand... Sorry for step jump
Subhotosh Khan said: View attachment 28636 This is excellent for an answer in a test. For homework, I would add: a2xy + b2xy + abx2 + aby2 = a2xy + abx2 + aby2 + b2xy = ax*(ay + bx) + by*(ay + by) = (ay + bx) * ( ax + by) Click to expand... Sorry for step jump