Probably super easy but. Fill in the missing numbers

Math user 2020

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This question is probably easier than I am making it out to be.

My child has been set this by their year 5 teacher and I am struggling!
 
1st you were dividing by two, then dividing by four. So the denominator got doubled (2*2=4) so you need to double the numerator. Continuing using 8/2, the numerator became 32 which is 4*8 so multiply the denominator by 4. Then the number became 64 which is 8*8, so multiple the denominator by 8 as well. This is how I would like a student to solve this problem.
 
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This question is probably easier than I am making it out to be.

My child has been set this by their year 5 teacher and I am struggling!
This is the problem I have here.

[math]8 \div 2 = 4[/math]
So the first square should be 4.

[math]8 \div 2 = 4 \div 4 = 1[/math]
So this says [math]8 \div 2 = 1[/math]!

etc.

Bad problem statement!

-Dan
 
This is the problem I have here.

[math]8 \div 2 = 4[/math]
So the first square should be 4.

[math]8 \div 2 = 4 \div 4 = 1[/math]
So this says [math]8 \div 2 = 1[/math]!

etc.

Bad problem statement!

-Dan
Dan, sorry but I disagree with you here. Of course it is true that 8÷2=4. But the problem does not asked that question. The problem is 8÷2 = what ÷ 4.

If you have 2+3 = x +7 you would not say that 2+3=x, so x=5. I am not clear at all why in this problem you choose to not read the whole problem but instead choose to read just part of it(??)
 
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