sniperkiller
New member
- Joined
- Jul 7, 2005
- Messages
- 2
Hi, I'm trying to get this question right, and no matter how often I look back at past papers, it just doesn't make sense to me.
Seven horses run a race. All horses finish the race and no two horses finish the race at the same time.
(i)In how many different orders can the seven horses finish the race?
I think this is right: 7!, which is 7.6.5.4.3.2.1, 5040.
(ii)A person is asked to predict the correct order of the first 3 horses to finish the race. How many such predictions can be made?
Hmmm. Not sure of this.
(iii)A person is asked to predict, in any order, the first 3 horses to finish the race. How many such predictions can be made?
I think this is: 7!/(7-3)!, which is 7!/4!, = 210.
Anyway, I'd be grateful for any help,
Regards,
Chris.
Seven horses run a race. All horses finish the race and no two horses finish the race at the same time.
(i)In how many different orders can the seven horses finish the race?
I think this is right: 7!, which is 7.6.5.4.3.2.1, 5040.
(ii)A person is asked to predict the correct order of the first 3 horses to finish the race. How many such predictions can be made?
Hmmm. Not sure of this.
(iii)A person is asked to predict, in any order, the first 3 horses to finish the race. How many such predictions can be made?
I think this is: 7!/(7-3)!, which is 7!/4!, = 210.
Anyway, I'd be grateful for any help,
Regards,
Chris.