Probability

mth22

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Mar 16, 2011
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A drawer contains 6 black socks, 4 gray socks and 2 blue socks. You randomly pick one sock from the drawere, then randomly pick another sock, without replacing the first sock. What are the odds of both socks being gray?
 
6+4+2 = 12

p(first is gray) = 4 / 12

p(second is gray|first was gray) = You tell me.

RBGTHGANH
 
mth22 said:
A drawer contains 6 black socks, 4 gray socks and 2 blue socks. You randomly pick one sock from the drawere, then randomly pick another sock, without replacing the first sock. What are the odds of both socks being gray?
HINT: probability 1st sock is grey is 4 / (6 + 4 + 2)
If you don't follow, you need classroom help.
 
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