Probability

[valnadam]

A man rolls an ordinary die 6 times. What is the probability that he gets at least 5 threes? Round your answer to four decimal places.I'm new at Statistics and don't know where to start with this problem. Thanks

 

[pka]

A man rolls an ordinary die 6 times. What is the probability that he gets at least 5 threes? Round your answer to four decimal places.I'm new at Statistics and don't know where to start with this problem. Thanks

That means either five threes or six threes.
\(\displaystyle \binom{6}{5}\left(\frac{1}{6}\right)^5\left(\frac{1}{6}\right)+\left(\frac{1}{6}\right)^6\)

 

[valnadam]

So do i put all thoses numers together? Looks like I have to multiply then add

 

[valnadam]

I got 0.0001500