Probability

[janig73]

Can anyone please help me with this Question?

1)The boarders at a kennel are made up of the following dogs.If one dog is randomly selected for a 30-minute training session, find the probability of each event.The fractions are written in simplest form.
Boarders

Males 10
Females 14
Pointers 6
Retrievers 18

i)P(retriever)
Answer options are:
A. 3/4 B.3/5 C.1/2 D.3/8

ii)P(not male)
A.19/24 B.7/12 C.1/2 D.7/24

iii)P(cat)
A.0 B.1/100 C.1/2 D.1

 

[tkhunny]

Notice how 10+14 = 24 and 18 + 6 = 24. This suggests that there are no terriers or cats or anythign else. Do you see why?

There are 24 dogs.

P(Retriever) = ?? / 24

P(not male) = 1 - P(female) = 1 - (?? / 24)

P(cat) = P(not a dog) = 0