The probability of a car with five worn tires will experience a blowout is 0.50. The probability of completing a trip with no more than one blowout is ?
Lets start with the four on car tires.
The probability of completing the trip on those is (0.5)<SUP>4</SUP>.
The probability at exactly one of those will fail 4(0.5)<SUP>4</SUP>.
Now we change to the spare and start out again.
The probability of completing the trip on those is (0.5)<SUP>4</SUP>.
Therefore, to complete the trip we must have no failures or exactly one.
(0.5)<SUP>4</SUP>+4(0.5)<SUP>4</SUP>(0.5)<SUP>4</SUP>=(0.5)<SUP>4</SUP>(1+4(0.5)<SUP>4</SUP>).
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