Probability

Stefan.andrea1988

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Consider the following (modified) sports draw: There are 30 teams divided evenly into 6 pots.

Then 5 groups with 6 teams each are formed. Each group is randomly assigned a team from each pot

drawn. Team A is in Pot 1 and Team B is in Pot 2. What is the probability that both teams are in the same group
 
Consider the following (modified) sports draw: There are 30 teams divided evenly into 6 pots.

Then 5 groups with 6 teams each are formed. Each group is randomly assigned a team from each pot

drawn. Team A is in Pot 1 and Team B is in Pot 2. What is the probability that both teams are in the same group
What does the following statement mean:

Each group is randomly assigned a team from each pot drawn

Please show us what you have tried and exactly where you are stuck.

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Please share your work/thoughts about this problem
 
Consider the following (modified) sports draw: There are 30 teams divided evenly into 6 pots.

Then 5 groups with 6 teams each are formed. Each group is randomly assigned a team from each pot

drawn.
I think I understand this situation. You have 6 pots. Initially each pot contains 5 teams.

Then, one team is drawn randomly, without replacement, from each pot. This gives us 6 teams, and these are called, say, group "g1".
The above process is repeated to obtain groups g2, g3, g4 and g5 (at which point all the pots will be empty).

Is this correct? If so, then your question makes sense...

Team A is in Pot 1 and Team B is in Pot 2. What is the probability that both teams are in the same group

Is this a real-life situation/ problem? Have you studied probability (and if so, then can you share your thoughts on this problem)?
 
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