Question is:
A sales crew has 10 males and 10 females. They need to form a group of 6 people. When choosing at random, what is the probability that the group will consist of 3 males and 3 females?
I know that probability would set the problem up as:
---10!--------- 10!
3!(10-3)! x 3!(10-3)!
---------20!
-----6!(20-6)!
I figured out the top portion using a calculator and the X! button. It would be:
120 x 120
----20!
6!(20-6)!
I cannot fugure out how to calculate the bottom of the problem. I tried 20! on the calculator and it came up with something like 2.432902008^18. I do not know how to incorporate that into the problem. Can someone please assist me? Hope this makes sense. I couldn't get the spaces lined up like I wanted to so I used dashes to line it up. Thanks so much in advance
A sales crew has 10 males and 10 females. They need to form a group of 6 people. When choosing at random, what is the probability that the group will consist of 3 males and 3 females?
I know that probability would set the problem up as:
---10!--------- 10!
3!(10-3)! x 3!(10-3)!
---------20!
-----6!(20-6)!
I figured out the top portion using a calculator and the X! button. It would be:
120 x 120
----20!
6!(20-6)!
I cannot fugure out how to calculate the bottom of the problem. I tried 20! on the calculator and it came up with something like 2.432902008^18. I do not know how to incorporate that into the problem. Can someone please assist me? Hope this makes sense. I couldn't get the spaces lined up like I wanted to so I used dashes to line it up. Thanks so much in advance
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