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Guest
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The odds in favour of a Pythag-Air-Us Airlines flight being on time are 3:1.
a) What is the probability that this airline's next eight flights will be on time?
so since odds are 3:1, Prob. should be 3/4, then q (number of failures) should be 1/4
I thought it was going to be like: (1/4)^7* 3/4. but thats wrong. The ans. is 0.1001. How'd they get that?
b) What is the expected waiting time before a flight delay?
I know that the formula is q/p but I can't get the right answer is I do 1/4 / 3/4.
Help please?
Thanks so much
a) What is the probability that this airline's next eight flights will be on time?
so since odds are 3:1, Prob. should be 3/4, then q (number of failures) should be 1/4
I thought it was going to be like: (1/4)^7* 3/4. but thats wrong. The ans. is 0.1001. How'd they get that?
b) What is the expected waiting time before a flight delay?
I know that the formula is q/p but I can't get the right answer is I do 1/4 / 3/4.
Help please?
Thanks so much