probability that the two females=partners in game?

[Guest]

Four friends, two females and two males, are playing contract bridge. Partners are randomly assigned for each game. What is the probability that the two females will be partners for the first game?

I thought it was 1/ 4C2 (since there are 4 people and need to be in 2(partners), but the answer is 1/3, how'd they get that.

Thanks

 

[pka]

The friends are \(\displaystyle F_1 ,F_2 ,M_1 ,M_2\) and the possible pairings are
\(\displaystyle \begin{array}{l}
\left[ {F_1 ,F_2 } \right];\left[ {M_1 ,M_2 } \right] \\
\left[ {F_1 ,M_2 } \right];\left[ {M_1 ,F_2 } \right] \\
\left[ {M_1 ,F_1 } \right];\left[ {F_2 ,M_2 } \right] \\
\end{array}\).

1/3 RIGHT?