Let D_n be the probability of getting two heads in a row in n coin tosses. Prove that D_n → 1 if n → ∞. Please explain in detail how to prove this.
The first thing to make sure we know what this means.
I would guess that "getting two heads in a row in n coin tosses" means that we toss a coin n times, and
somewhere in the sequence of n results,
at least two successive tosses are heads. So it would be a succes (with n=5) if we tossed THHTT, or THHTH, or HHTHH, or HHHTH , or even HHHHH (and others).
I would tend to try the
complement: What is the probability that there will
never be two H's in a row? Then you need to count events like TTTTT, and THTHT, and HTTTH. Do you have any ideas about that? (Or any approach, for that matter?)
I suppose it's also conceivable that you could prove the claim without ever making a formula for D_n. What have you learned that might be useful either way? (Knowing your context can help us a lot, in knowing both what sort of help is appropriate, and how hard a problem to expect this to be!)